Table of contents
Description
Question Links: LeetCode 380
Implement the RandomizedSet class:
RandomizedSet()Initializes the RandomizedSet object.bool insert(int val)Inserts an itemvalinto the set if not present. Returnstrueif the item was not present,falseotherwise.bool remove(int val)Removes an itemvalfrom the set if present. Returnstrueif the item was present,falseotherwise.int getRandom()Returns a random element from the current set of elements (it’s guaranteed that at least one element exists when this method is called). Each element must have the same probability of being returned.
You must implement the functions of the class such that each function works in average O(1) time complexity.
Example 1:
Input
["RandomizedSet", "insert", "remove", "insert", "getRandom", "remove", "insert", "getRandom"]
[[], [1], [2], [2], [], [1], [2], []]
Output
[null, true, false, true, 2, true, false, 2]
Explanation
RandomizedSet randomizedSet = new RandomizedSet();
randomizedSet.insert(1); // Inserts 1 to the set. Returns true as 1 was inserted successfully.
randomizedSet.remove(2); // Returns false as 2 does not exist in the set.
randomizedSet.insert(2); // Inserts 2 to the set, returns true. Set now contains [1,2].
randomizedSet.getRandom(); // getRandom() should return either 1 or 2 randomly.
randomizedSet.remove(1); // Removes 1 from the set, returns true. Set now contains [2].
randomizedSet.insert(2); // 2 was already in the set, so return false.
randomizedSet.getRandom(); // Since 2 is the only number in the set, getRandom() will always return 2.
Constraints:
- At most calls will be made to
insert,remove, andgetRandom. - There will be at least one element in the data structure when
getRandomis called.
Solution
Idea
The key insight is that we need O(1) for three different operations:
- insert — checking membership and adding: use a hash map.
- remove — finding and removing: hash map gives O(1) lookup, but we also need O(1) removal from the collection used by
getRandom. - getRandom — uniform random access by index: use a dynamic array (ArrayList/Vec).
The trick for O(1) removal from the array is to swap the element to remove with the last element, then pop the last. The hash map stores val -> index so we can locate any element in the array instantly.
Before remove(val=3):
Array: [5, 3, 8, 7] Map: {5:0, 3:1, 8:2, 7:3}
^
Step 1: swap with last
Array: [5, 7, 8, 7] Map: {5:0, 7:1, 8:2, ...}
Step 2: pop last, remove from map
Array: [5, 7, 8] Map: {5:0, 7:1, 8:2}
Complexity: Time average for all operations, Space .
Java
class RandomizedSet {
ArrayList<Integer> nums;
HashMap<Integer, Integer> valIndex; // val -> index in nums
Random rand;
public RandomizedSet() {
nums = new ArrayList<>();
valIndex = new HashMap<>();
rand = new Random();
}
public boolean insert(int val) {
if (valIndex.containsKey(val)) return false; // O(1) lookup
valIndex.put(val, nums.size());
nums.add(val); // O(1) amortized append
return true;
}
public boolean remove(int val) {
if (!valIndex.containsKey(val)) return false; // O(1) lookup
int i = valIndex.get(val);
if (i < nums.size() - 1) { // swap with last, O(1)
int last = nums.get(nums.size() - 1);
nums.set(i, last);
valIndex.put(last, i);
}
valIndex.remove(val);
nums.remove(nums.size() - 1); // O(1) pop from end
return true;
}
public int getRandom() {
return nums.get(rand.nextInt(nums.size())); // O(1) random index
}
}
Python
class RandomizedSet:
def __init__(self):
self.vals = []
self.val_index = {}
def insert(self, val: int) -> bool:
if val in self.val_index: # O(1) hash lookup
return False
self.val_index[val] = len(self.vals)
self.vals.append(val) # O(1) amortized append
return True
def remove(self, val: int) -> bool:
if val not in self.val_index: # O(1) hash lookup
return False
i = self.val_index[val]
last = self.vals[-1]
self.vals[i] = last # O(1) swap last into removed slot
self.val_index[last] = i
self.vals.pop() # O(1) pop from end
del self.val_index[val]
return True
def getRandom(self) -> int:
return random.choice(self.vals) # O(1) random index access
C++
class RandomizedSet {
vector<int> nums;
unordered_map<int, int> valToIdx; // val -> index in nums
public:
RandomizedSet() {}
bool insert(int val) {
if (valToIdx.count(val)) return false; // O(1) lookup
valToIdx[val] = nums.size();
nums.push_back(val); // O(1) amortized
return true;
}
bool remove(int val) {
if (!valToIdx.count(val)) return false; // O(1) lookup
int idx = valToIdx[val];
int last = nums.back();
nums[idx] = last; // O(1) swap with last
valToIdx[last] = idx;
nums.pop_back(); // O(1) pop
valToIdx.erase(val);
return true;
}
int getRandom() {
return nums[rand() % nums.size()]; // O(1)
}
};
Rust
use rand::Rng;
use std::collections::HashMap;
struct RandomizedSet {
vals: Vec<i32>,
val_index: HashMap<i32, usize>,
}
impl RandomizedSet {
fn new() -> Self {
Self { vals: Vec::new(), val_index: HashMap::new() }
}
fn insert(&mut self, val: i32) -> bool {
if self.val_index.contains_key(&val) { // O(1) lookup
return false;
}
self.val_index.insert(val, self.vals.len());
self.vals.push(val); // O(1) amortized
true
}
fn remove(&mut self, val: i32) -> bool {
if let Some(&idx) = self.val_index.get(&val) { // O(1) lookup
let last = *self.vals.last().unwrap();
self.vals[idx] = last; // O(1) swap with last
self.val_index.insert(last, idx);
self.vals.pop(); // O(1) pop
self.val_index.remove(&val);
true
} else {
false
}
}
fn get_random(&self) -> i32 {
let mut rng = rand::thread_rng();
let idx = rng.gen_range(0..self.vals.len()); // O(1)
self.vals[idx]
}
}